Optimal. Leaf size=192 \[ \frac {2 a \left (15 c^2+10 c d+7 d^2\right ) (-7 A d+B c-6 B d) \cos (e+f x)}{105 d f \sqrt {a \sin (e+f x)+a}}+\frac {2 d (-7 A d+B c-6 B d) \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{35 a f}+\frac {4 (5 c-d) (-7 A d+B c-6 B d) \cos (e+f x) \sqrt {a \sin (e+f x)+a}}{105 f}-\frac {2 a B \cos (e+f x) (c+d \sin (e+f x))^3}{7 d f \sqrt {a \sin (e+f x)+a}} \]
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Rubi [A] time = 0.34, antiderivative size = 192, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 37, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.108, Rules used = {2981, 2761, 2751, 2646} \[ \frac {2 a \left (15 c^2+10 c d+7 d^2\right ) (-7 A d+B c-6 B d) \cos (e+f x)}{105 d f \sqrt {a \sin (e+f x)+a}}+\frac {2 d (-7 A d+B c-6 B d) \cos (e+f x) (a \sin (e+f x)+a)^{3/2}}{35 a f}+\frac {4 (5 c-d) (-7 A d+B c-6 B d) \cos (e+f x) \sqrt {a \sin (e+f x)+a}}{105 f}-\frac {2 a B \cos (e+f x) (c+d \sin (e+f x))^3}{7 d f \sqrt {a \sin (e+f x)+a}} \]
Antiderivative was successfully verified.
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Rule 2646
Rule 2751
Rule 2761
Rule 2981
Rubi steps
\begin {align*} \int \sqrt {a+a \sin (e+f x)} (A+B \sin (e+f x)) (c+d \sin (e+f x))^2 \, dx &=-\frac {2 a B \cos (e+f x) (c+d \sin (e+f x))^3}{7 d f \sqrt {a+a \sin (e+f x)}}+\frac {(7 a A d-B (a c-6 a d)) \int \sqrt {a+a \sin (e+f x)} (c+d \sin (e+f x))^2 \, dx}{7 a d}\\ &=\frac {2 d (B c-7 A d-6 B d) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{35 a f}-\frac {2 a B \cos (e+f x) (c+d \sin (e+f x))^3}{7 d f \sqrt {a+a \sin (e+f x)}}+\frac {(2 (7 a A d-B (a c-6 a d))) \int \sqrt {a+a \sin (e+f x)} \left (\frac {1}{2} a \left (5 c^2+3 d^2\right )+a (5 c-d) d \sin (e+f x)\right ) \, dx}{35 a^2 d}\\ &=\frac {4 (5 c-d) (B c-7 A d-6 B d) \cos (e+f x) \sqrt {a+a \sin (e+f x)}}{105 f}+\frac {2 d (B c-7 A d-6 B d) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{35 a f}-\frac {2 a B \cos (e+f x) (c+d \sin (e+f x))^3}{7 d f \sqrt {a+a \sin (e+f x)}}+\frac {\left (\left (15 c^2+10 c d+7 d^2\right ) (7 a A d-B (a c-6 a d))\right ) \int \sqrt {a+a \sin (e+f x)} \, dx}{105 a d}\\ &=\frac {2 a (B c-7 A d-6 B d) \left (15 c^2+10 c d+7 d^2\right ) \cos (e+f x)}{105 d f \sqrt {a+a \sin (e+f x)}}+\frac {4 (5 c-d) (B c-7 A d-6 B d) \cos (e+f x) \sqrt {a+a \sin (e+f x)}}{105 f}+\frac {2 d (B c-7 A d-6 B d) \cos (e+f x) (a+a \sin (e+f x))^{3/2}}{35 a f}-\frac {2 a B \cos (e+f x) (c+d \sin (e+f x))^3}{7 d f \sqrt {a+a \sin (e+f x)}}\\ \end {align*}
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Mathematica [A] time = 0.74, size = 176, normalized size = 0.92 \[ -\frac {\sqrt {a (\sin (e+f x)+1)} \left (\cos \left (\frac {1}{2} (e+f x)\right )-\sin \left (\frac {1}{2} (e+f x)\right )\right ) \left (\left (56 A d (5 c+2 d)+B \left (140 c^2+224 c d+141 d^2\right )\right ) \sin (e+f x)-6 d (7 A d+14 B c+6 B d) \cos (2 (e+f x))+420 A c^2+560 A c d+266 A d^2+280 B c^2+532 B c d-15 B d^2 \sin (3 (e+f x))+228 B d^2\right )}{210 f \left (\sin \left (\frac {1}{2} (e+f x)\right )+\cos \left (\frac {1}{2} (e+f x)\right )\right )} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.43, size = 306, normalized size = 1.59 \[ \frac {2 \, {\left (15 \, B d^{2} \cos \left (f x + e\right )^{4} + 3 \, {\left (14 \, B c d + {\left (7 \, A + 6 \, B\right )} d^{2}\right )} \cos \left (f x + e\right )^{3} - 35 \, {\left (3 \, A + B\right )} c^{2} - 14 \, {\left (5 \, A + 7 \, B\right )} c d - {\left (49 \, A + 27 \, B\right )} d^{2} - {\left (35 \, B c^{2} + 14 \, {\left (5 \, A + B\right )} c d + {\left (7 \, A + 36 \, B\right )} d^{2}\right )} \cos \left (f x + e\right )^{2} - {\left (35 \, {\left (3 \, A + 2 \, B\right )} c^{2} + 14 \, {\left (10 \, A + 11 \, B\right )} c d + 11 \, {\left (7 \, A + 6 \, B\right )} d^{2}\right )} \cos \left (f x + e\right ) + {\left (15 \, B d^{2} \cos \left (f x + e\right )^{3} + 35 \, {\left (3 \, A + B\right )} c^{2} + 14 \, {\left (5 \, A + 7 \, B\right )} c d + {\left (49 \, A + 27 \, B\right )} d^{2} - 3 \, {\left (14 \, B c d + {\left (7 \, A + B\right )} d^{2}\right )} \cos \left (f x + e\right )^{2} - {\left (35 \, B c^{2} + 14 \, {\left (5 \, A + 4 \, B\right )} c d + {\left (28 \, A + 39 \, B\right )} d^{2}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right ) + a}}{105 \, {\left (f \cos \left (f x + e\right ) + f \sin \left (f x + e\right ) + f\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: NotImplementedError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.44, size = 161, normalized size = 0.84 \[ \frac {2 \left (1+\sin \left (f x +e \right )\right ) a \left (\sin \left (f x +e \right )-1\right ) \left (-15 B \left (\cos ^{2}\left (f x +e \right )\right ) \sin \left (f x +e \right ) d^{2}+\left (70 A c d +28 A \,d^{2}+35 B \,c^{2}+56 B c d +39 B \,d^{2}\right ) \sin \left (f x +e \right )+\left (-21 A \,d^{2}-42 B c d -18 B \,d^{2}\right ) \left (\cos ^{2}\left (f x +e \right )\right )+105 A \,c^{2}+140 A c d +77 A \,d^{2}+70 B \,c^{2}+154 B c d +66 B \,d^{2}\right )}{105 \cos \left (f x +e \right ) \sqrt {a +a \sin \left (f x +e \right )}\, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (B \sin \left (f x + e\right ) + A\right )} \sqrt {a \sin \left (f x + e\right ) + a} {\left (d \sin \left (f x + e\right ) + c\right )}^{2}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \left (A+B\,\sin \left (e+f\,x\right )\right )\,\sqrt {a+a\,\sin \left (e+f\,x\right )}\,{\left (c+d\,\sin \left (e+f\,x\right )\right )}^2 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {a \left (\sin {\left (e + f x \right )} + 1\right )} \left (A + B \sin {\left (e + f x \right )}\right ) \left (c + d \sin {\left (e + f x \right )}\right )^{2}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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